Quiz on Transfer Functions
Information for Questions 1-3: Two reactors are operated in parallel and the output of each is mixed in a blending tank. The inputs (`U_1` and `U_2`) are cooling jacket temperatures. The reactor outputs (`X_1` and `X_2`) are reactor concentrations that are mixed (`X_3`) and blended (`Y`).
1. What is the expression for reactor outlet `X_2` in terms of input `U_2`?
- Incorrect. Use the transfer function `G_2` and input `U_2`
- Incorrect. Use the transfer function `G_2`
- Correct. The transfer function `G_2` relates the input `U_2` to the output `X_2`
- Incorrect. Use the transfer function `G_2` and input `U_2`
2. What is the expression for the mixed reactor outlet `X_3` in terms of inputs `U_1` and `U_2`?
- Incorrect. Processes in parallel are additive, not multiplicative
- Incorrect. Use transfer functions `G_1` and `G_2` instead of `X_1` and `X_2`
- Incorrect. This is correct but it is not in terms of the inputs
- Correct. `X_3 = X_1 + X_2 = G_1 U_1 + G_2 U_2`
3. What is the expression for the blender outlet `Y` in terms of inputs `U_1` and `U_2`?
- Incorrect. This is correct but not in terms of `U_1` and `U_2`
- Incorrect. This is correct but not in terms of `U_1` and `U_2`
- Correct. This is in terms of the inputs `U_1` and `U_2` and the transfer functions
- Incorrect. The intermediate signals `X_1`, `X_2`, and `X_3` are not in the input to output expression
4. What are the requirements to obtain a transfer function? Select two correct answers.
- Incorrect. Only linear equations or linearized nonlinear equations can be transformed to Laplace domain
- Correct. Only linear equations can be transformed to Laplace domain
- Incorrect. A transfer function relates one input to one output
- Correct. A transfer function relates one input to one output
5. What is the gain of the transfer function `G(s) = {5(s + 1)}/{(s + 3)^2}`?
- Incorrect. `K_p = \lim_{s \to 0} {5(s + 1)}/{(s + 3)^2}`
- Correct. `K_p = \lim_{s \to 0} {5(s + 1)}/{(s + 3)^2} = {5(1)}/{3^2} = 5/9`
- Incorrect. `K_p = \lim_{s \to 0} {5(s + 1)}/{(s + 3)^2}`
- Incorrect. `K_p = \lim_{s \to 0} {5(s + 1)}/{(s + 3)^2}`